In the above figure, O is the center of the circle and, M and N lie on the circle.

The area of the right triangle MON is 50 cm^{2}.

What is the area of the circle in cm^{2}?

This question was previously asked in

GATE ME 2021 Official Paper: Shift 1

- 2π
- 100π
- 75π
- 50π

Option 2 : 100π

__ Concept__:

Area of Right-angled triangle = \(\frac{1}{2}× base × height\)

Area of the traingle = πr^{2}

__ Calculation__:

__ Given__:

ON = OM = Base of triangle = Height of triangle = Radius, Area of triangle = 50 cm^{2}.

Area of Right-angled triangle = \(\frac{1}{2}× base × height\)

\(\frac{1}{2}× Radius × Radius =50\)

∴ Radius = 10 cm

Area of the circle = πr2 = π × 10 × 10 = 100π cm^{2}.

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CT 1: Ratio and Proportion

3941

10 Questions
16 Marks
30 Mins

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