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TNTRB 2012 ME Official Question Paper

Option 2 : 981 N/m^{2}

__Concept:__

**Pressure head** is given by:

**\(\frac{{{P_1} - {P_2}}}{{\rho g}} = h\left( {\frac{{{S_m}}}{S} - 1} \right)\)**

__Calculation:__

__Given:__

ρ_{m} = 2000 kg/m^{3 }⇒ S_{m} = 2, S = 1, h = 10 cm = 0.1 m

We know that

\(\frac{{{P_1} - {P_2}}}{{\rho g}} = h\left( {\frac{{{S_m}}}{S} - 1} \right)\)

\({{{P_1} - {P_2}}}{{}} = \rho gh\left( {\frac{{{S_m}}}{S} - 1} \right)\)

ΔP = 1000 × 9.81 × 0.1 × (2 - 1)

**ΔP = 981 N/m ^{2}**

ST 1: Building Material and Concrete Technology

20275

20 Questions
20 Marks
12 Mins